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(F)=-5/8F+16
We move all terms to the left:
(F)-(-5/8F+16)=0
Domain of the equation: 8F+16)!=0We get rid of parentheses
F∈R
F+5/8F-16=0
We multiply all the terms by the denominator
F*8F-16*8F+5=0
Wy multiply elements
8F^2-128F+5=0
a = 8; b = -128; c = +5;
Δ = b2-4ac
Δ = -1282-4·8·5
Δ = 16224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16224}=\sqrt{2704*6}=\sqrt{2704}*\sqrt{6}=52\sqrt{6}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-52\sqrt{6}}{2*8}=\frac{128-52\sqrt{6}}{16} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+52\sqrt{6}}{2*8}=\frac{128+52\sqrt{6}}{16} $
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