F(x)=-x2+4

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Solution for F(x)=-x2+4 equation:



(F)=-F2+4
We move all terms to the left:
(F)-(-F2+4)=0
We add all the numbers together, and all the variables
-(-1F^2+4)+F=0
We get rid of parentheses
1F^2+F-4=0
We add all the numbers together, and all the variables
F^2+F-4=0
a = 1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*1}=\frac{-1-\sqrt{17}}{2} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*1}=\frac{-1+\sqrt{17}}{2} $

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