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(F)=0-F2
We move all terms to the left:
(F)-(0-F2)=0
We add all the numbers together, and all the variables
-(-1F^2+0)+F=0
We get rid of parentheses
1F^2+F-0=0
We add all the numbers together, and all the variables
F^2+F=0
a = 1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1}=\frac{-2}{2} =-1 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1}=\frac{0}{2} =0 $
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