F(x)=0.4(x-10)2+40

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Solution for F(x)=0.4(x-10)2+40 equation: 



(F)=0.4(F-10)2+40

We move all terms to the left:

(F)-(0.4(F-10)2+40)=0



We calculate terms in parentheses: -(0.4(F-10)2+40), so:

0.4(F-10)2+40

We multiply parentheses

0.8F-8+40

We add all the numbers together, and all the variables

0.8F+32

Back to the equation:

-(0.8F+32)



We get rid of parentheses

F-0.8F-32=0

We add all the numbers together, and all the variables

0.2F-32=0

We move all terms containing F to the left, all other terms to the right

0.2F=32

F=32/0.2

F=160

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