F(x)=1/2(2C)+7=1/3(2C)+3

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Solution for F(x)=1/2(2C)+7=1/3(2C)+3 equation: 



(F)=1/2(2)+7=1/3(2)+3

We move all terms to the left:

(F)-(1/2(2)+7)=0

We get rid of parentheses

F-7-1/22=0

We multiply all the terms by the denominator


F*22-1-7*22=0

We add all the numbers together, and all the variables

F*22-155=0

Wy multiply elements

22F-155=0

We move all terms containing F to the left, all other terms to the right

22F=155

F=155/22

F=7+1/22

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