F(x)=10/3x+2

Solution for F(x)=10/3x+2 equation:

(F)=10/3F+2

We move all terms to the left:

(F)-(10/3F+2)=0


Domain of the equation: 3F+2)!=0

F∈R


We get rid of parentheses

F-10/3F-2=0

We multiply all the terms by the denominator


F*3F-2*3F-10=0

Wy multiply elements

3F^2-6F-10=0

a = 3; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·3·(-10)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{39}}{2*3}=\frac{6-2\sqrt{39}}{6}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{39}}{2*3}=\frac{6+2\sqrt{39}}{6}
$