F(x)=10x+11/5x+4

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Solution for F(x)=10x+11/5x+4 equation: 



(F)=10F+11/5F+4

We move all terms to the left:

(F)-(10F+11/5F+4)=0



Domain of the equation: 5F+4)!=0

F∈R



We get rid of parentheses

F-10F-11/5F-4=0

We multiply all the terms by the denominator


F*5F-10F*5F-4*5F-11=0

Wy multiply elements

5F^2-50F^2-20F-11=0

We add all the numbers together, and all the variables

-45F^2-20F-11=0

a = -45; b = -20; c = -11;
Δ = b2-4ac
Δ = -202-4·(-45)·(-11)
Δ = -1580
Delta is less than zero, so there is no solution for the equation

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