F(x)=2(4-x-5)+15

Solution for F(x)=2(4-x-5)+15 equation:

(F)=2(4-F-5)+15

We move all terms to the left:

(F)-(2(4-F-5)+15)=0

We add all the numbers together, and all the variables

F-(2(-1F-1)+15)=0


We calculate terms in parentheses: -(2(-1F-1)+15), so:

2(-1F-1)+15

We multiply parentheses

-2F-2+15

We add all the numbers together, and all the variables

-2F+13

Back to the equation:

-(-2F+13)


We get rid of parentheses

F+2F-13=0

We add all the numbers together, and all the variables

3F-13=0

We move all terms containing F to the left, all other terms to the right

3F=13

F=13/3

F=4+1/3