F(x)=2(5x-4)+3x

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Solution for F(x)=2(5x-4)+3x equation: 



(F)=2(5F-4)+3F

We move all terms to the left:

(F)-(2(5F-4)+3F)=0



We calculate terms in parentheses: -(2(5F-4)+3F), so:

2(5F-4)+3F

We add all the numbers together, and all the variables

3F+2(5F-4)

We multiply parentheses

3F+10F-8

We add all the numbers together, and all the variables

13F-8

Back to the equation:

-(13F-8)



We get rid of parentheses

F-13F+8=0

We add all the numbers together, and all the variables

-12F+8=0

We move all terms containing F to the left, all other terms to the right

-12F=-8

F=-8/-12

F=2/3

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