F(x)=2(x+2)-5

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Solution for F(x)=2(x+2)-5 equation: 



(F)=2(F+2)-5

We move all terms to the left:

(F)-(2(F+2)-5)=0



We calculate terms in parentheses: -(2(F+2)-5), so:

2(F+2)-5

We multiply parentheses

2F+4-5

We add all the numbers together, and all the variables

2F-1

Back to the equation:

-(2F-1)



We get rid of parentheses

F-2F+1=0

We add all the numbers together, and all the variables

-1F+1=0

We move all terms containing F to the left, all other terms to the right

-F=-1

F=-1/-1

F=1

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