F(x)=2/3x+9

Solution for F(x)=2/3x+9 equation:

(F)=2/3F+9

We move all terms to the left:

(F)-(2/3F+9)=0


Domain of the equation: 3F+9)!=0

F∈R


We get rid of parentheses

F-2/3F-9=0

We multiply all the terms by the denominator


F*3F-9*3F-2=0

Wy multiply elements

3F^2-27F-2=0

a = 3; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·3·(-2)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{753}}{2*3}=\frac{27-\sqrt{753}}{6}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{753}}{2*3}=\frac{27+\sqrt{753}}{6}
$