F(x)=2/5x+11

Solution for F(x)=2/5x+11 equation:

(F)=2/5F+11

We move all terms to the left:

(F)-(2/5F+11)=0


Domain of the equation: 5F+11)!=0

F∈R


We get rid of parentheses

F-2/5F-11=0

We multiply all the terms by the denominator


F*5F-11*5F-2=0

Wy multiply elements

5F^2-55F-2=0

a = 5; b = -55; c = -2;
Δ = b2-4ac
Δ = -552-4·5·(-2)
Δ = 3065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{3065}}{2*5}=\frac{55-\sqrt{3065}}{10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{3065}}{2*5}=\frac{55+\sqrt{3065}}{10}
$