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(F)=2F-10/F-10
We move all terms to the left:
(F)-(2F-10/F-10)=0
Domain of the equation: F-10)!=0We get rid of parentheses
F∈R
F-2F+10/F+10=0
We multiply all the terms by the denominator
F*F-2F*F+10*F+10=0
We add all the numbers together, and all the variables
10F+F*F-2F*F+10=0
Wy multiply elements
F^2-2F^2+10F+10=0
We add all the numbers together, and all the variables
-1F^2+10F+10=0
a = -1; b = 10; c = +10;
Δ = b2-4ac
Δ = 102-4·(-1)·10
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{35}}{2*-1}=\frac{-10-2\sqrt{35}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{35}}{2*-1}=\frac{-10+2\sqrt{35}}{-2} $
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