F(x)=2x2-3x+5

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Solution for F(x)=2x2-3x+5 equation:



(F)=2F^2-3F+5
We move all terms to the left:
(F)-(2F^2-3F+5)=0
We get rid of parentheses
-2F^2+F+3F-5=0
We add all the numbers together, and all the variables
-2F^2+4F-5=0
a = -2; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-2)·(-5)
Δ = -24
Delta is less than zero, so there is no solution for the equation

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