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(F)=3(F)2+6
We move all terms to the left:
(F)-(3(F)2+6)=0
We add all the numbers together, and all the variables
-(+3F^2+6)+F=0
We get rid of parentheses
-3F^2+F-6=0
a = -3; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-3)·(-6)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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