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(F)=3/F+2
We move all terms to the left:
(F)-(3/F+2)=0
Domain of the equation: F+2)!=0We get rid of parentheses
F∈R
F-3/F-2=0
We multiply all the terms by the denominator
F*F-2*F-3=0
We add all the numbers together, and all the variables
-2F+F*F-3=0
Wy multiply elements
F^2-2F-3=0
a = 1; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·1·(-3)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4}{2*1}=\frac{-2}{2} =-1 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4}{2*1}=\frac{6}{2} =3 $
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