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(F)=3F/2F-7
We move all terms to the left:
(F)-(3F/2F-7)=0
Domain of the equation: 2F-7)!=0We get rid of parentheses
F∈R
F-3F/2F+7=0
We multiply all the terms by the denominator
F*2F-3F+7*2F=0
We add all the numbers together, and all the variables
-3F+F*2F+7*2F=0
Wy multiply elements
2F^2-3F+14F=0
We add all the numbers together, and all the variables
2F^2+11F=0
a = 2; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·2·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*2}=\frac{-22}{4} =-5+1/2 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*2}=\frac{0}{4} =0 $
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