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(F)=3F/F-4F
We move all terms to the left:
(F)-(3F/F-4F)=0
Domain of the equation: F-4F)!=0We add all the numbers together, and all the variables
F∈R
F-(-4F+3F/F)=0
We get rid of parentheses
F+4F-3F/F=0
We multiply all the terms by the denominator
F*F+4F*F-3F=0
We add all the numbers together, and all the variables
-3F+F*F+4F*F=0
Wy multiply elements
F^2+4F^2-3F=0
We add all the numbers together, and all the variables
5F^2-3F=0
a = 5; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·5·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*5}=\frac{0}{10} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*5}=\frac{6}{10} =3/5 $
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