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(F)=3F/F-5
We move all terms to the left:
(F)-(3F/F-5)=0
Domain of the equation: F-5)!=0We get rid of parentheses
F∈R
F-3F/F+5=0
We multiply all the terms by the denominator
F*F-3F+5*F=0
We add all the numbers together, and all the variables
2F+F*F=0
Wy multiply elements
F^2+2F=0
a = 1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*1}=\frac{-4}{2} =-2 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*1}=\frac{0}{2} =0 $
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