F(x)=3x2+5x+4

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Solution for F(x)=3x2+5x+4 equation: 



(F)=3F^2+5F+4

We move all terms to the left:

(F)-(3F^2+5F+4)=0

We get rid of parentheses

-3F^2+F-5F-4=0

We add all the numbers together, and all the variables

-3F^2-4F-4=0

a = -3; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-3)·(-4)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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