F(x)=3x2-10

Solution for F(x)=3x2-10 equation:

(F)=3F^2-10

We move all terms to the left:

(F)-(3F^2-10)=0

We get rid of parentheses

-3F^2+F+10=0

a = -3; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-3)·10
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-3}=\frac{-12}{-6}
=+2
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-3}=\frac{10}{-6}
=-1+2/3
$