F(x)=3x2-5x+13

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Solution for F(x)=3x2-5x+13 equation: 



(F)=3F^2-5F+13

We move all terms to the left:

(F)-(3F^2-5F+13)=0

We get rid of parentheses

-3F^2+F+5F-13=0

We add all the numbers together, and all the variables

-3F^2+6F-13=0

a = -3; b = 6; c = -13;
Δ = b2-4ac
Δ = 62-4·(-3)·(-13)
Δ = -120
Delta is less than zero, so there is no solution for the equation

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