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(F)=4/3F-7
We move all terms to the left:
(F)-(4/3F-7)=0
Domain of the equation: 3F-7)!=0We get rid of parentheses
F∈R
F-4/3F+7=0
We multiply all the terms by the denominator
F*3F+7*3F-4=0
Wy multiply elements
3F^2+21F-4=0
a = 3; b = 21; c = -4;
Δ = b2-4ac
Δ = 212-4·3·(-4)
Δ = 489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{489}}{2*3}=\frac{-21-\sqrt{489}}{6} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{489}}{2*3}=\frac{-21+\sqrt{489}}{6} $
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