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(F)=42/F
We move all terms to the left:
(F)-(42/F)=0
Domain of the equation: F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
F-(+42/F)=0
We get rid of parentheses
F-42/F=0
We multiply all the terms by the denominator
F*F-42=0
Wy multiply elements
F^2-42=0
a = 1; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·1·(-42)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{42}}{2*1}=\frac{0-2\sqrt{42}}{2} =-\frac{2\sqrt{42}}{2} =-\sqrt{42} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{42}}{2*1}=\frac{0+2\sqrt{42}}{2} =\frac{2\sqrt{42}}{2} =\sqrt{42} $
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