F(x)=4X+10-16X2

Solution for F(x)=4X+10-16X2 equation:

(F)=4F+10-16F^2

We move all terms to the left:

(F)-(4F+10-16F^2)=0

We get rid of parentheses

16F^2-4F+F-10=0

We add all the numbers together, and all the variables

16F^2-3F-10=0

a = 16; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·16·(-10)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{649}}{2*16}=\frac{3-\sqrt{649}}{32}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{649}}{2*16}=\frac{3+\sqrt{649}}{32}
$