F(x)=4x/2x+2

Solution for F(x)=4x/2x+2 equation:

(F)=4F/2F+2

We move all terms to the left:

(F)-(4F/2F+2)=0


Domain of the equation: 2F+2)!=0

F∈R


We get rid of parentheses

F-4F/2F-2=0

We multiply all the terms by the denominator


F*2F-4F-2*2F=0

We add all the numbers together, and all the variables

-4F+F*2F-2*2F=0

Wy multiply elements

2F^2-4F-4F=0

We add all the numbers together, and all the variables

2F^2-8F=0

a = 2; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*2}=\frac{0}{4}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*2}=\frac{16}{4}
=4
$