F(x)=5(1/4)x-4

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Solution for F(x)=5(1/4)x-4 equation: 



(F)=5(1/4)F-4

We move all terms to the left:

(F)-(5(1/4)F-4)=0



Domain of the equation: 4)F-4)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

F-(5(+1/4)F-4)=0

We multiply all the terms by the denominator


F*4)F-4)-(5(+1=0

Wy multiply elements

4F^2+1=0

a = 4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4·1
Δ = -16
Delta is less than zero, so there is no solution for the equation

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