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(F)=5/F+4
We move all terms to the left:
(F)-(5/F+4)=0
Domain of the equation: F+4)!=0We get rid of parentheses
F∈R
F-5/F-4=0
We multiply all the terms by the denominator
F*F-4*F-5=0
We add all the numbers together, and all the variables
-4F+F*F-5=0
Wy multiply elements
F^2-4F-5=0
a = 1; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·1·(-5)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6}{2*1}=\frac{-2}{2} =-1 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6}{2*1}=\frac{10}{2} =5 $
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