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(F)=5/F-14+10
We move all terms to the left:
(F)-(5/F-14+10)=0
Domain of the equation: F-14+10)!=0We add all the numbers together, and all the variables
We move all terms containing F to the left, all other terms to the right
F+10)!=14
F∈R
F-(5/F-4)=0
We get rid of parentheses
F-5/F+4=0
We multiply all the terms by the denominator
F*F+4*F-5=0
We add all the numbers together, and all the variables
4F+F*F-5=0
Wy multiply elements
F^2+4F-5=0
a = 1; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·1·(-5)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6}{2*1}=\frac{-10}{2} =-5 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6}{2*1}=\frac{2}{2} =1 $
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