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(F)=5F(2)-2F+4
We move all terms to the left:
(F)-(5F(2)-2F+4)=0
We add all the numbers together, and all the variables
-(+5F^2-2F+4)+F=0
We get rid of parentheses
-5F^2+2F+F-4=0
We add all the numbers together, and all the variables
-5F^2+3F-4=0
a = -5; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-5)·(-4)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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