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(F)=5F/F+1
We move all terms to the left:
(F)-(5F/F+1)=0
Domain of the equation: F+1)!=0We get rid of parentheses
F∈R
F-5F/F-1=0
We multiply all the terms by the denominator
F*F-5F-1*F=0
We add all the numbers together, and all the variables
-6F+F*F=0
Wy multiply elements
F^2-6F=0
a = 1; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*1}=\frac{12}{2} =6 $
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