F(x)=5x2+50x-124

Solution for F(x)=5x2+50x-124 equation:

(F)=5F^2+50F-124

We move all terms to the left:

(F)-(5F^2+50F-124)=0

We get rid of parentheses

-5F^2+F-50F+124=0

We add all the numbers together, and all the variables

-5F^2-49F+124=0

a = -5; b = -49; c = +124;
Δ = b2-4ac
Δ = -492-4·(-5)·124
Δ = 4881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{4881}}{2*-5}=\frac{49-\sqrt{4881}}{-10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{4881}}{2*-5}=\frac{49+\sqrt{4881}}{-10}
$