F(x)=6/5x+3

Solution for F(x)=6/5x+3 equation:

(F)=6/5F+3

We move all terms to the left:

(F)-(6/5F+3)=0


Domain of the equation: 5F+3)!=0

F∈R


We get rid of parentheses

F-6/5F-3=0

We multiply all the terms by the denominator


F*5F-3*5F-6=0

Wy multiply elements

5F^2-15F-6=0

a = 5; b = -15; c = -6;
Δ = b2-4ac
Δ = -152-4·5·(-6)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{345}}{2*5}=\frac{15-\sqrt{345}}{10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{345}}{2*5}=\frac{15+\sqrt{345}}{10}
$