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(F)=6F+10/2F
We move all terms to the left:
(F)-(6F+10/2F)=0
Domain of the equation: 2F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
F-(+6F+10/2F)=0
We get rid of parentheses
F-6F-10/2F=0
We multiply all the terms by the denominator
F*2F-6F*2F-10=0
Wy multiply elements
2F^2-12F^2-10=0
We add all the numbers together, and all the variables
-10F^2-10=0
a = -10; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-10)·(-10)
Δ = -400
Delta is less than zero, so there is no solution for the equation
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