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(F)=7F(F-3)
We move all terms to the left:
(F)-(7F(F-3))=0
We calculate terms in parentheses: -(7F(F-3)), so:We get rid of parentheses
7F(F-3)
We multiply parentheses
7F^2-21F
Back to the equation:
-(7F^2-21F)
-7F^2+F+21F=0
We add all the numbers together, and all the variables
-7F^2+22F=0
a = -7; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-7)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-7}=\frac{-44}{-14} =3+1/7 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-7}=\frac{0}{-14} =0 $
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