F(x)=7x-4/x+3

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Solution for F(x)=7x-4/x+3 equation:



(F)=7F-4/F+3
We move all terms to the left:
(F)-(7F-4/F+3)=0
Domain of the equation: F+3)!=0
F∈R
We get rid of parentheses
F-7F+4/F-3=0
We multiply all the terms by the denominator
F*F-7F*F-3*F+4=0
We add all the numbers together, and all the variables
-3F+F*F-7F*F+4=0
Wy multiply elements
F^2-7F^2-3F+4=0
We add all the numbers together, and all the variables
-6F^2-3F+4=0
a = -6; b = -3; c = +4;
Δ = b2-4ac
Δ = -32-4·(-6)·4
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*-6}=\frac{3-\sqrt{105}}{-12} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*-6}=\frac{3+\sqrt{105}}{-12} $

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