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(F)=8F/F-3
We move all terms to the left:
(F)-(8F/F-3)=0
Domain of the equation: F-3)!=0We get rid of parentheses
F∈R
F-8F/F+3=0
We multiply all the terms by the denominator
F*F-8F+3*F=0
We add all the numbers together, and all the variables
-5F+F*F=0
Wy multiply elements
F^2-5F=0
a = 1; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·1·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*1}=\frac{10}{2} =5 $
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