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(F)=9/7F-3
We move all terms to the left:
(F)-(9/7F-3)=0
Domain of the equation: 7F-3)!=0We get rid of parentheses
F∈R
F-9/7F+3=0
We multiply all the terms by the denominator
F*7F+3*7F-9=0
Wy multiply elements
7F^2+21F-9=0
a = 7; b = 21; c = -9;
Δ = b2-4ac
Δ = 212-4·7·(-9)
Δ = 693
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{693}=\sqrt{9*77}=\sqrt{9}*\sqrt{77}=3\sqrt{77}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3\sqrt{77}}{2*7}=\frac{-21-3\sqrt{77}}{14} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3\sqrt{77}}{2*7}=\frac{-21+3\sqrt{77}}{14} $
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