F(x)=9/9x+11

Solution for F(x)=9/9x+11 equation:

(F)=9/9F+11

We move all terms to the left:

(F)-(9/9F+11)=0


Domain of the equation: 9F+11)!=0

F∈R


We get rid of parentheses

F-9/9F-11=0

We multiply all the terms by the denominator


F*9F-11*9F-9=0

Wy multiply elements

9F^2-99F-9=0

a = 9; b = -99; c = -9;
Δ = b2-4ac
Δ = -992-4·9·(-9)
Δ = 10125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10125}=\sqrt{2025*5}=\sqrt{2025}*\sqrt{5}=45\sqrt{5}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-45\sqrt{5}}{2*9}=\frac{99-45\sqrt{5}}{18}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+45\sqrt{5}}{2*9}=\frac{99+45\sqrt{5}}{18}
$