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(F)=9/F-8
We move all terms to the left:
(F)-(9/F-8)=0
Domain of the equation: F-8)!=0We get rid of parentheses
F∈R
F-9/F+8=0
We multiply all the terms by the denominator
F*F+8*F-9=0
We add all the numbers together, and all the variables
8F+F*F-9=0
Wy multiply elements
F^2+8F-9=0
a = 1; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·1·(-9)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*1}=\frac{-18}{2} =-9 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*1}=\frac{2}{2} =1 $
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