F(x)=ln(2x-3)2

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Solution for F(x)=ln(2x-3)2 equation:


Simplifying
F(x) = ln(2x + -3) * 2

Multiply F * x
xF = ln(2x + -3) * 2

Reorder the terms:
xF = ln(-3 + 2x) * 2

Reorder the terms for easier multiplication:
xF = 2ln(-3 + 2x)
xF = (-3 * 2ln + 2x * 2ln)
xF = (-6ln + 4lnx)

Solving
xF = -6ln + 4lnx

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4lnx' to each side of the equation.
-4lnx + xF = -6ln + 4lnx + -4lnx

Combine like terms: 4lnx + -4lnx = 0
-4lnx + xF = -6ln + 0
-4lnx + xF = -6ln

Reorder the terms:
6ln + -4lnx + xF = -6ln + 6ln

Combine like terms: -6ln + 6ln = 0
6ln + -4lnx + xF = 0

The solution to this equation could not be determined.

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