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(F)=F(56-F)
We move all terms to the left:
(F)-(F(56-F))=0
We add all the numbers together, and all the variables
F-(F(-1F+56))=0
We calculate terms in parentheses: -(F(-1F+56)), so:We get rid of parentheses
F(-1F+56)
We multiply parentheses
-1F^2+56F
Back to the equation:
-(-1F^2+56F)
1F^2-56F+F=0
We add all the numbers together, and all the variables
F^2-55F=0
a = 1; b = -55; c = 0;
Δ = b2-4ac
Δ = -552-4·1·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-55}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+55}{2*1}=\frac{110}{2} =55 $
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