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(F)=F(F-14)
We move all terms to the left:
(F)-(F(F-14))=0
We calculate terms in parentheses: -(F(F-14)), so:We get rid of parentheses
F(F-14)
We multiply parentheses
F^2-14F
Back to the equation:
-(F^2-14F)
-F^2+F+14F=0
We add all the numbers together, and all the variables
-1F^2+15F=0
a = -1; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-1)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-1}=\frac{-30}{-2} =+15 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-1}=\frac{0}{-2} =0 $
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