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(F)=F(26-2F)
We move all terms to the left:
(F)-(F(26-2F))=0
We add all the numbers together, and all the variables
F-(F(-2F+26))=0
We calculate terms in parentheses: -(F(-2F+26)), so:We get rid of parentheses
F(-2F+26)
We multiply parentheses
-2F^2+26F
Back to the equation:
-(-2F^2+26F)
2F^2-26F+F=0
We add all the numbers together, and all the variables
2F^2-25F=0
a = 2; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·2·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*2}=\frac{0}{4} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*2}=\frac{50}{4} =12+1/2 $
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