F(x)=x+4/(x-5)(x+3)

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Solution for F(x)=x+4/(x-5)(x+3) equation: 



(F)=F+4/(F-5)(F+3)

We move all terms to the left:

(F)-(F+4/(F-5)(F+3))=0



Domain of the equation: (F-5)(F+3))!=0

F∈R



We multiply parentheses ..

-(F+4/(+F^2+3F-5F-15))+F=0

We multiply all the terms by the denominator


-(F+4+F*(+F^2+3F-5F-15))=0



We calculate terms in parentheses: -(F+4+F*(+F^2+3F-5F-15)), so:

F+4+F*(+F^2+3F-5F-15)

determiningTheFunctionDomain
F*(+F^2+3F-5F-15)+F+4

We multiply parentheses

F^3+3F^2-5F^2-15F+F+4

We do not support eFpression: F^3

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