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(F)=F/5F+8
We move all terms to the left:
(F)-(F/5F+8)=0
Domain of the equation: 5F+8)!=0We get rid of parentheses
F∈R
F-F/5F-8=0
We multiply all the terms by the denominator
F*5F-F-8*5F=0
We add all the numbers together, and all the variables
-1F+F*5F-8*5F=0
Wy multiply elements
5F^2-1F-40F=0
We add all the numbers together, and all the variables
5F^2-41F=0
a = 5; b = -41; c = 0;
Δ = b2-4ac
Δ = -412-4·5·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-41}{2*5}=\frac{0}{10} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+41}{2*5}=\frac{82}{10} =8+1/5 $
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