F(x)=x2+-100

Solution for F(x)=x2+-100 equation:

(F)=F2+-100

We move all terms to the left:

(F)-(F2+-100)=0

We add all the numbers together, and all the variables

-(+F^2+-100)+F=0

We use the square of the difference formula

-(+F^2-100)+F=0

We get rid of parentheses

-F^2+F+100=0

We add all the numbers together, and all the variables

-1F^2+F+100=0

a = -1; b = 1; c = +100;
Δ = b2-4ac
Δ = 12-4·(-1)·100
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{401}}{2*-1}=\frac{-1-\sqrt{401}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{401}}{2*-1}=\frac{-1+\sqrt{401}}{-2}
$