F(x)=x2+3x-21

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Solution for F(x)=x2+3x-21 equation:



(F)=F2+3F-21
We move all terms to the left:
(F)-(F2+3F-21)=0
We add all the numbers together, and all the variables
-(+F^2+3F-21)+F=0
We get rid of parentheses
-F^2-3F+F+21=0
We add all the numbers together, and all the variables
-1F^2-2F+21=0
a = -1; b = -2; c = +21;
Δ = b2-4ac
Δ = -22-4·(-1)·21
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{22}}{2*-1}=\frac{2-2\sqrt{22}}{-2} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{22}}{2*-1}=\frac{2+2\sqrt{22}}{-2} $

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