F(x)=x2+4x+3

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Solution for F(x)=x2+4x+3 equation:



(F)=F2+4F+3
We move all terms to the left:
(F)-(F2+4F+3)=0
We add all the numbers together, and all the variables
-(+F^2+4F+3)+F=0
We get rid of parentheses
-F^2-4F+F-3=0
We add all the numbers together, and all the variables
-1F^2-3F-3=0
a = -1; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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