F(x)=x2+5.

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Solution for F(x)=x2+5. equation: 



(F)=F2+5.

We move all terms to the left:

(F)-(F2+5.)=0

We add all the numbers together, and all the variables

-(+F^2+5.)+F=0

We get rid of parentheses

-F^2+F-5.=0

We add all the numbers together, and all the variables

-1F^2+F-5=0

a = -1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation

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